Posted by admin | Posted in Build a Shed | Posted on 13-04-2011
Tags: build shed roof truss design, how to build shed roof trusses

Math word problem, algebra?
I will build a 12 'x16'x12' shed. I'm going to build my own trusses cover. Here is a picture of how I'm going to do that. To hang on the bottom of the deck of a foot. How many should I buy 2×4 and how long? I'm so lost on this problem. I do not know what to do. The strip is rectangle so maybe I should use the Pythagorean theorem. I do not know. Any help would be great.
I assume the trusses will extend the width of 12 '. Moreover, I assume the peak will run in the middle, with sides symmetrical. Therefore, needs 6 "of horizontal run, plus 1 'for the projection of a total of 7 feet. You have not stated the height you want the peak, or what it costs you want the ceiling. I'll use an example here: the peak is 2 "higher than the eaves. If you draw a triangle, it will be easier to see, but will have a triangle with two legs, 2 and 7. Use the Pythagorean theorem to find the hypotenuse, which is the length of the sloping part one side of the roof. This is √ (49 + 4) = √ 53 ≈ 7.28 meters. But remember, this is in theory. In practice, you must cut the angles at the ends of the 2×4 is what you'll need a little more. 8 'will be fine. If instead you have a slope (4-12 pitch is common), then the angle of the roof is arctan (4.12) = 18.4 degrees. To find the length of the slope, taking the race (7) divided by the cosine of the angle: 7 / cos 18.4 = 7.38 meters.
Building a roof with trusses on a tool shed
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